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2w^2+2w-144=0
a = 2; b = 2; c = -144;
Δ = b2-4ac
Δ = 22-4·2·(-144)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-34}{2*2}=\frac{-36}{4} =-9 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+34}{2*2}=\frac{32}{4} =8 $
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